Math, asked by nitika2763, 1 year ago

find equation of tangent to the curve y=(x3-1)(x-2) at the points where the curve cut x-axis

Answers

Answered by shashankdubey9876

0

y=3xsquare-6x-x+3

on differentiation, we get

y'= 6x - 7

which is the equation of tangent

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