find equation of the circle which passes through points(1,0),(-1,0)and(0,1)
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Answer:
x² + y² = 1
Step-by-step explanation:
The general equation of the a circle is (x-a)² + (y-b)² = c²
Here, a=0
b=0
c=1
∴ Equation of the circle is x² + y² = 1
Sharmaankit:
tq bhaiii
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