find equation of the line passing through the points(-3,5) perpendicular to the point (1,0)(-4,1)
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slope = (1-0) / (-4-1)
= -1/5
now slope of given line = 5
equation of line
y - 5 = 5(x -(-3))
y-5 = 5x +15
y = 5x +20
5x - y +20 = 0
is equation of line .
hope it can help you .....✌✌
= -1/5
now slope of given line = 5
equation of line
y - 5 = 5(x -(-3))
y-5 = 5x +15
y = 5x +20
5x - y +20 = 0
is equation of line .
hope it can help you .....✌✌
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