Question

Find equation. Whose zeroes are 3 and ±√2

Answer 1

Answer:

$k{{ {x}^{2} - ( \alpha + \beta )x + \alpha \beta }$

sum of the zero=3+√2

product of the zeroes=3×√2=3√2

k[x²-(3+√2)x+3√2]

when k=1

the required quadratic equation=x²-3-√2x+3√2