Question

find equations of the straight line passing through the points (-4;6) (6;8)​

Answer 1

Answer:

$let \: \\ the \: coordinates \: of \: point \: ( - 4.6)is \: x1 = - 4 \: and \: y1 = 6 \\ the \: coordinate \: of \: point \: (6.8)is \: x2 = 6 \: and \: y2 = 8 \\ the \: equation \: of \: line \: in \: two \: point \: form \\ \frac{x - x1}{x1 - x2} = \frac{y - y1}{y1 - y2} \\ \frac{x - ( - 4)}{ - 4 - 6} = \frac{y - 6}{6 - 8} \\ \frac{x + 4}{ - 10} = \frac{y - 6}{ - 2} \\ - 2(x + 4) = - 10(y - 6) \\ - 2x - 8 = - 10y + 60 \\ - 8 - 60 = 2x - 10y \\ - 68 = 2x - 10y \\ 2x - 10y + 68 = 0 \\ 2(x - 5y + 34) = 0 \\ x - 5y + 34 = 0 \\ the \: equation \: of \: line \: is \: x - 5y + 34 = 0.$