Question

The frequency distribution of marks obtained by 36 student in a test are as follows
Marks obtained no. Of students
50-60 4
60-70 8
70-80 12
80-90 6
90-100 6
draw commulative curves of less than and more than type ogive on the same axis and from them determine the median

Answer 1

$\Longrightarrow{\boxed{\bold{Answer: 12}}}$

$\textbf{\underline{Step-by-step explanation :- }}$

Please refer to attachment!

Now, here n is odd i.e., 5 frequencies.

Therefore, median = [ ( n + 1 )/2 ]th position

$= {( \frac{n + 1}{2} )}^{th} \\ \\ = {( \frac{5 + 1}{2}) }^{th} \\ \\ = {( \frac{6}{2}) }^{th} = {3}^{th}$

$\textbf{\underline{Here, 3th position is 12.}}$

Answer 2

Median = 75

Step-by-step explanation:

marks     f      more than    Less than

50-60      4       36               4

60-70      8       32                12

70-80      12      24                24

80-90       6       12                30

90-100      6       6                 36

Median = 75

70 + 10 *(18 - 12)/12  = 70 + 5 = 75

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