find equivalent resistance between C and D
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4Ω and 2Ω are in series with each other and both are parallel to 6 Ω
Therefore equivalent resistance = (4 + 2)*6/((4+2) + 6) = 4 Ω
Therefore equivalent resistance = (4 + 2)*6/((4+2) + 6) = 4 Ω
foley:
the equation that you made gives answer 3 ohm not 4 ohm . by the wey thanks
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