find equivalent resistance between P and Q
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Answer:
(2Rr)/r+R
Explanation:
the two 2R (vertical) in the center will act as Wheatstones bridge ,thus neglect it
R(series)1=4R
" " 2=2r
" " 3=4R
there are in parallel thus
R(parallel )=(2rR)/r+R
(1/Rp=1/R1+1/R2+.....)
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