Find equivalent resistance between points A and B
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Explanation:
Since R(AB) and R(BC) are in series
Therefore
R1 = R(AB) + R(BC)
R1 = 2 ohm + 1 ohm = 3 ohm
R1 = 3 ohm
Since R(AD) and R(DC) are in series
Therefore
R2 = R(AD) + R(DC)
R2 = 2 ohm + 1 ohm = 3 ohm
R2 = 3 ohm
Since R1 , R2 and R(AC) are in Parralel
Therefore
1 / R = 1/R1 + 1/R2 + 1/R(AC)
1 / R = 1/3 ohm + 1/3 ohm + 1/3 ohm = 3/3 ohm
1 / R = 1 ohm
R = 1 ohm
Therefore Total Resistance Offered is 1 ohm
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