Find equivalent resistance between points A and B for the network shown in the figure.
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Answer:
First find the resistance of middle they are connected into series
R
S
=3R+3R
R
S
=6R
And this 6R resistor is parallel to B side resistor
R
P
=
6R+3R
3R×6R
==2R
So finally resistance between A and B is
R
S
1
=2R+R=3R
Hence,
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