find out the share of b among rs.396 such that a gets 3/5 of what b gets and b gets1/5 of what c gets?
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Answer:
Let,
A gets x
B gets y
C gets z
Acc to condition 1
x+y+z = 395 {eq 1
Now B gets 25% more than A
→ y = x + 25%x
→ y = x + x/4
→ y = 5x/4
→ x = 4y/5 {eq 2
Also B gets 20% more than C
→ y = z + 20%z
→ y = z + z/5
→ y = 6z/5
→ z = 5y/6 {eq 3
Now put values of x (eq 1) and z(eq 2) in eq 1
4y/5 + y + 5y/6 = 395
Take LCM, solve the eq for y, you get
y = 150
Put vaue of y in eq 2 & eq 3 you get
x = 120
z = 125
So A’s share is 120/395
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