find equivalent resistance if three resistances are joined in series and parallel combination with two examples
Answers
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PARALLEL COMBINATION :-
Consider 3 resistors in parallel ( R1 ,R2 and R3 . )
Total current ( I )
• Current in 3 branches = I1 , I2 and I3
• Total voltage = V
=> I = I1 + I2 + I3
=> I1 = V / R1
=> I2 = V /R2
=> I3 = V / R3
I1 + I2 + I3 = V / R1 + V / R2 + V / R3
Let equivalent resistance be ( Re )
=> Re = V / I => I = V / Re
=> V / Re = V/ R1 + V / R2 + V / R3
♦ => 1 / Re = 1 / R1 + 1 / R2 + 1 / R3
=> In parallel combination the equivalent resistance is the sum of reciprocal of the individual resistance
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SERIES COMBINATION:-
Consider 3 resistors , R1 , R2 and R3 connected in series .
By Ohm' Law the potential drop across each resistor is given by :-
=> V1 = IR1
=> V2 = IR2
=> V3 = IR3
Let total potential be ( V )
V = V1 + V2 + V3
V = IRe ( Re is the equivalent resistance . )
Thus ,,
•• IRe = IR1 + IR2 + IR3
♦ Re = R1 + R2 + R3 .
we can say that equivalent resistance in series combination is the individual sum of resistance .
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PARALLEL COMBINATION :-
Consider 3 resistors in parallel ( R1 ,R2 and R3 . )
Total current ( I )
• Current in 3 branches = I1 , I2 and I3
• Total voltage = V
=> I = I1 + I2 + I3
=> I1 = V / R1
=> I2 = V /R2
=> I3 = V / R3
I1 + I2 + I3 = V / R1 + V / R2 + V / R3
Let equivalent resistance be ( Re )
=> Re = V / I => I = V / Re
=> V / Re = V/ R1 + V / R2 + V / R3
♦ => 1 / Re = 1 / R1 + 1 / R2 + 1 / R3
=> In parallel combination the equivalent resistance is the sum of reciprocal of the individual resistance
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SERIES COMBINATION:-
Consider 3 resistors , R1 , R2 and R3 connected in series .
By Ohm' Law the potential drop across each resistor is given by :-
=> V1 = IR1
=> V2 = IR2
=> V3 = IR3
Let total potential be ( V )
V = V1 + V2 + V3
V = IRe ( Re is the equivalent resistance . )
Thus ,,
•• IRe = IR1 + IR2 + IR3
♦ Re = R1 + R2 + R3 .
we can say that equivalent resistance in series combination is the individual sum of resistance .
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