Question

find equivalent resistance in series in a +9V circuit where r1=r2=r3= r4=r5=2,r6=r9=4,r7=r8=8​

Answer 1

Answer:

R2 and R3 are in series so R23 = R2+R3 = 3+3 =6ohm

R23 is in parallel with R4 = 1/R234 = 1/6 + 1/3 = 1/2

R234 = 2 ohm

R1 , R5 and R234 is in series so R' = 3+3+2 = 8ohm

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Answer 2

The value of R1 = R2 = R3 = R4 = R5 = 2Ω

R6 = R9 = 4Ω

R7 = R8 = 8Ω

To find equivalent resistance -:

Rs = R1 + R2 + R3 + R4 + R5 + R6 + R7 + R8 + R9

Rs = 2Ω + 4Ω + 8Ω

Rs = 14Ω