Find everything for a parabola when tangent at vertex 3x-4y=5 and focus is (1,2)?
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Answered by
0
Answer:
use this method please mark as brainliest it helps me a lot
Step-by-step explanation:
9y
2
−16x−12y−57=0
So (y−
3
2
)
2
=
9
16
(x+
16
61
)
i.e; y
2
=4ax.
Vertex is (
16
−61
,
3
2
).
This axis is y−
3
2
=0
y=
3
2
directrix is :x+a=0
x+
16
61
+
9
4
=0
x=−613/144.
Focus is x=a & y=0
x+61/16=4/9 and
y−2/3=0.
(−485/144,2/3) is focus
Length of latus rectum
=4A=16/9
Tangent at vertex is
X=0
X=
16
−61
.
Answered by
0
Answer:
Step-by-step explanation:
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