Math, asked by pushkar2781, 9 hours ago

Find everything for a parabola when tangent at vertex 3x-4y=5 and focus is (1,2)?

Answers

Answered by swaritgamer
0

Answer:

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Step-by-step explanation:

9y

2

−16x−12y−57=0

So (y−

3

2

)

2

=

9

16

(x+

16

61

)

i.e; y

2

=4ax.

Vertex is (

16

−61

,

3

2

).

This axis is y−

3

2

=0

y=

3

2

directrix is :x+a=0

x+

16

61

+

9

4

=0

x=−613/144.

Focus is x=a & y=0

x+61/16=4/9 and

y−2/3=0.

(−485/144,2/3) is focus

Length of latus rectum

=4A=16/9

Tangent at vertex is

X=0

X=

16

−61

.

Answered by arsharma478
0

Answer:

Step-by-step explanation:

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