Question

Find f(-1) for the equation \\(y=2xy^{2}-4x+1)

Answer 1

Answer:

f(-1)=X|(-1)

y=2xy²-4x+1

y=2y²(-1)-4(-1)+1

y=-2y²+5

2y²+y+5=0

x=

$\frac{ - b + - \sqrt{b^{2} - 4ac} }{2a}$

X

$= \frac{ - 1+ - \sqrt{1 - 40} }{4}$

x

$\frac{ - 1 + - \sqrt{39} }{4}$

x

$= \frac{ - 1 + \sqrt{39} }{4} or \frac{ - 1 - \sqrt{39} }{4}$