Question

please solve any if you can. ASAP

Answer 1

Here, out of 14 gm on N only 80% is converted into N2O3.
So, amout of N actually participating in the reaction=(80/100) ×14= 11.2 gm

Now 11.2 gm contains, (11.2÷14) ×6.022×10^23 atoms= 4.82×10^23 atoms

2 N atoms require 3 O atoms to form N2O3.
So, for one N atom we need 3/2 O atoms.

Total number of oxygen atoms required = 4.82 ×(3/2) ×10^23 atoms=7.22 ×10^23 atoms

Hope this helps!