Question

how much a body of weight 35 n will weight in water, if it displace one litre of water ? (g= 9.8m sec ^-2)

Answer 1

weight of body = 35N
Body displaces one litre of water .
∵ Archimedes theory ,
weight of body in water = weigh of body in air - weight of water displaced by body

∵ 1 litre of water is displaced by body
∴ volume of water = 1 L
we know, density of water = 1000 kg/m³
Hence, mass of water = 1L × 1000 kg/m³
= 10⁻³ × 1000 kg [ ∵ 1L = 10⁻³ m³ ]
= 1kg

Now, weight of body in water = 35N - 1kg × 9.8 m/s² [ ∵ weight = mass × g]
= 35 N - 9.8N = 25.2N

Answer 2

Hello Dear.

Here is the answer---


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Given,

Weight of the Body in air = 35 N.

Amount of Water displaced by the Body = 1 liter

        For Changing Liter into m³,
 
       1 m³ = 1000 liter
Thus, 1 liter = 10⁻³ m³

Using the Formula,
  
   Density = Mass/Volume
Density of the Water = 100 kg/m³

Thus, 1000 = Mass/10⁻³

⇒ Mass = 1 kg.

Using the Formula,

    Weight = Mass × Acceleration Due to Gravity
                = 1 × 10    [Since, Taking, g = 10 m/s²]
                = 10 N.

Now,

As per as the Archimedes Principle = 

Weight of the Body in water = Weight of the Body in air - Amount of water displaced by the body

         Weight in water = 35 - 10
                                  = 25 N.


Thus, the weights of the body in water is 25 N.


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Hope it helps.


Have a Marvelous Day.