Question

find f(-2)+ f(1), if f(x) = x^2+3x+1​

Answer 1

f(x)=x

2

−3x+1

f(2α)=(2α)

2

−3(2α)+1=4α

2

−6α+1

f(2α)=2f(α)

∴4α

2

−6α+1=2(α

2

−3α+1)

4α

2

−6α+1=2α

2

−bα+2

4α

2

+1=2α

2

+2

2α

2

=1 α=±

2

1

Hope, this is helpful

Answer 2

Step-by-step explanation:

f(-2)= (-2)² + 3(-2)+1

= 4 -6 +1

= -1

f(1)= (1)² + 3 (1) +1

= 1+3+1

=5

f(-2) + f(1)

-1 + 5

4