Question

Find Factorize of: (x–y)^2+4x​y
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Answer 1

$\huge \mathscr{\orange {\underline {\pink{\underline{Answer :-}}}}}$

$\tt{−4x+4y−y²}$

Rearranging:

$\tt{−x²-y²-4x+4yx² − y² −4x+4y}$

As we know

$\tt{a²-b²=(a+b)(a-b)a² −b²}$

$\tt{=(a+b)(a−b)}$

Now, back to your question.

$\tt{=(x+y)(x-y)-4(x-y) }$

$\tt{= (x+y)(x−y)−4(x−y)}$

$\tt{= (x+y-4)(x-y) }$

$\tt{= (x+y−4)(x−y)}$

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Answer 2

$\huge \mathscr{\orange {\underline {\pink{\underline{Answer :-}}}}}$

$\tt{−4x+4y−y²}$

★Rearranging :

$\tt{−x²-y²-4x+4yx² − y² −4x+4y}$

As we know

$\tt{a²-b²=(a+b)(a-b)a² −b²}$

$\tt{=(a+b)(a−b)}$

Now, back to your question.

$\tt{=(x+y)(x-y)-4(x-y) }$

$\tt{= (x+y)(x−y)−4(x−y)}$

$\tt{= (x+y-4)(x-y) }$

$\tt{= (x+y−4)(x−y)}$

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