Question

find find?????????????????

Answer 1

$\sf{Given \ figure \ is \ a \ rectangle.}$

$\therefore$

$\sf{Opposite \ sides \ are \ equal.}$

$\sf{i.e.}$

$\sf{x + y = 3x - 2y}$

$\sf{x - 3x + y + 2y = 0}$

$\sf{- 2x + 3y = 0}$

$\sf{2x - 3y = 0 \qquad \qquad \qquad ...( 1 )}$

$\sf{Also,}$

$\sf{x + 7 = y + 8}$

$\sf{x = y + 8 - 7}$

$\sf{x = y + 1 \qquad \qquad \qquad ...( 2 )}$

$\sf{Put \ ( 2 ) \ in \ ( 1 )}$

$\sf{2 ( y + 1 ) - 3y = 0}$

$\sf{2y + 2 - 3y = 0}$

$\sf{- y + 2 = 0}$

${\boxed{\sf{y = 2}}}$

$\sf{Put \ this \ value \ in \ ( 2 )}$

$\sf{x = 2 + 1}$

${\boxed{\sf{x = 3}}}$

$\sf{Now,}$

$\large\sf{Length \ -}$

$\sf{= x + 7}$

$\sf{= 3 + 7}$

$\large\sf\blue{= 10 \ unit}$

$\large\sf{Breadth \ -}$

$\sf{= x + y}$

$\sf{= 3 + 2}$

$\large\sf\blue{= 5 unit}$