Question

find the area of square whose perimeter is equal to the perimeter of rectangle of size 14 cmby 12 cm​

Answer 1

Answer:

169 cm^2

Step-by-step explanation:

gn

length of rectangle =14cm

breadth=12

perimeter = 2(l+b)

=2*(14+12)

=2*26=52=perimeter of square

side of square = 52/2 = 13

area of square = side^2

=13^2

=169cm^2

Answer 2

Answer:

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Find the area of square whose perimeter is equal to the perimeter of rectangle of size 14 cm by 12 cm.

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$\red{\bigstar}$ Area of square[A]

$\huge\leadsto{\sf\purple{169 \: cm}}$

$\Large{\underline{\underline{\bf{GiVen:-}}}}$

Perimeter of square whose perimeter is equal to the perimeter of rectangle.

Length of rectangle (l) = 14 cm

Breath of rectangle (b) = 12 cm

$\Large{\underline{\underline{\bf{Find:-}}}}$

❥ What's the area of a square ?

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

Here we go !

As we know ,

Perimeter of rectangle = 2 ( l + b )

↠ Perimeter of rectangle = 2(14 + 12)

↠ Perimeter of rectangle = 2(26)

↠ 52 cm

Now from the given :--

Square perimeter = 52 cm

First finding the side of square :-

Side of square = Square perimeter / Number of sides

Substituting the values :-

↠Side of square = 52/4

↠Side of square = 13 cm

What's the area of square is ?

Its just the square of sides

Area of square = (Side)²

Applying above formula

Area of square = (13)²

Area of square = 169 cm²

The area of square is 169 cm².

$\underline{\boxed{\textsf{ A = {\textbf{169 cm²}}}}} \qquad\qquad \bigg\lgroup\bold{Area \ of \ Square} \bigg\rgroup$

Additional Information :-

❥ Perimeter of Rectangle = 2( L + B )

❥ Perimeter of square = 4 × Side

❥ Perimeter of triangle = AB + BC + CA

❥ Area of Rectangle = L × B

❥ Area of Square = ( side ) ²

❥ Area of Rhombus = Product of Diagonal/2.

❥ Area of Parallelogram = Base × Height.

❥ Area of triangle = 1/2 × base × height .

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