Question

find find find find find​

Answer 1

Answer:

0

Hope this helps.

Step-by-step explanation:

With the restriction

0° < θ₁, θ₂, θ₃ < 90°

this is not possible since then

sin θ₁, sin θ₂, sin θ₃ < 1

=> sin θ₁ + sin θ₂ + sin θ₃ < 3.

But if we modify the problem to allow 0° ≤ θ₁, θ₂, θ₃ ≤ 90°  ( i.e. the end values are included ), then it is possible.

Since sin θ₁, sin θ₂, sin θ₃ ≤ 1, the only way to have

sin θ₁ + sin θ₂ + sin θ₃ = 3

is to have

sin θ₁ = sin θ₂ = sin θ₃ = 1

=> θ₁ = θ₂ = θ₃ = 90°

=> cos θ₁ = cos θ₂ = cos θ₃ = 0

=> cos θ₁ + cos θ₂ + cos θ₃ = 0