Question

Find find the area of semicircle whose circumference is 18m

Answer 1

Answer:

circumference = 2pi×r = 18

r = 18/2pi = 9pi

Area = pi × r^2

pi × (9pi)^2

= 81pi^3

Answer 2

Answer:

Area of Semicircle = 19.2325m²

Step-by-step explanation:

We Have :-

Perimeter of Semicircle = 18m

To Find :-

Area of Semicircle

Formula Used :-

Perimeter of Semicircle = πr + d

Area of Semicircle = πr²/2

Solution :-

$Perimeter = \pi r+d\\\\18 = \pi r+2r\\\\18 = 3.14r + 2r\\\\18 = 5.14r\\\\r = 3.5 m\\\\Area = \frac{3.14 * 3.5*3.5}{2} \\\\= 19.2325m^{2}$

Area of Semicircle = 19.2325m²