Question

Find Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40 square metres

Answer 1

HEYA!!!!

Here is your answer :

Given,

Perimeter of rectangle = 28mts

2 ( l + b ) = 28

2 (l + b ) = 28

l + b = 28/2

l + b = 14

l = 14 - b ---------(1)

Now area of rectangle = 40

l × b = 40

from eq 1

( 14-b ) × b = 40

Therefore, length of rectangle = 10 , breadth of rectangle =4..

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