Question

find first term of AP whose second term is 14 and common difference is 14

Answer 1

The A.P is given by a1,a1+d,a1+2d,......

so the first term is a1, the second term is given by a2= a1+d

Now, a2 = 14 and d =14

then a2 = a1+d

14 = a1 + 14

∴ the first term a1 = 0