find five consecutive terms in AP whose sun is 520 and product of first and the last to the product of second and fourth in 20:21
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let the terms be a - 4d , a - 2d , a , a +2d , a - 4d
given a - 4d + a - 2d + a + a +2d + a - 4d = 520
5a = 520
a = 104
so given that [( a - 4d ) (a - 4d)]/[ (a - 2d) (a +2d )] = 20/21
so solving for d after putting the value of a
we get d = 6.5
so the terms are a - 4×6.5 , a - 2×6.5 , a , a +2×6.5 , a - 4×6.5
that is
104 - 4×6.5, 104 - 2×6.5 , 104, 104 +2×6.5 , 104 - 4×6.5
that is 78, 91 , 104 , 117 , 130
given a - 4d + a - 2d + a + a +2d + a - 4d = 520
5a = 520
a = 104
so given that [( a - 4d ) (a - 4d)]/[ (a - 2d) (a +2d )] = 20/21
so solving for d after putting the value of a
we get d = 6.5
so the terms are a - 4×6.5 , a - 2×6.5 , a , a +2×6.5 , a - 4×6.5
that is
104 - 4×6.5, 104 - 2×6.5 , 104, 104 +2×6.5 , 104 - 4×6.5
that is 78, 91 , 104 , 117 , 130
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