Question

Find five numbers in AP whose sum is 12 and the ratio of the first to the last term is 2:3​

Answer 1

Answer:

Step-by-step explanation:

s=n/2(2a+(n-1)d)

12=5/2(2a+4d)

12=5(a+2d)

5a+10d=12

10d=12-5a

d=12-5a/10

a+4d=a+4*(12-5a/10)=a+2/5*(12-5a)=a+24/5-2a=4.8-a

a+4d/a=3/2

2a+8d=3a

a=8d

a=8(12-5a/10)

a=4/5(12-5a)

a=48/5-4a

5a=48/5

a=48/25

d=48/25*8=6/25

terms are 48/25,54/25,60/25,66/25,72,25