find five rational number between . 3/5 and 4/5 .
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0
There are a variety of processes to do this type of sum .
I am doing in one way-
1. 1/2(3/4 + 4/5)
= 1/2(31/20)
=31/40
2. 1/2(3/4 + 31/40)
=1/2(61/40)
=61/80
3. 1/2(4/5 +31/40)
= 1/2(63/40)
= 63/80
4. 1/2(3/4 + 61/80)
=1/2(121/80)
=121/160
5. 1/2(4/5 + 63/80)
= 1/2(127/80)
= 127/160
So, the required rational numbers are:- 31/40, 61/80, 63/80, 121/160, 123/160.
:))
I am doing in one way-
1. 1/2(3/4 + 4/5)
= 1/2(31/20)
=31/40
2. 1/2(3/4 + 31/40)
=1/2(61/40)
=61/80
3. 1/2(4/5 +31/40)
= 1/2(63/40)
= 63/80
4. 1/2(3/4 + 61/80)
=1/2(121/80)
=121/160
5. 1/2(4/5 + 63/80)
= 1/2(127/80)
= 127/160
So, the required rational numbers are:- 31/40, 61/80, 63/80, 121/160, 123/160.
:))
Answered by
3
hey guy here is u...
now we get the value of d..
then find (x+d),(x+2d)(x+3d)x+4d)(x+5d).
hope it helps u...
now we get the value of d..
then find (x+d),(x+2d)(x+3d)x+4d)(x+5d).
hope it helps u...
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Anonymous:
u get lost
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