Question

Find focal length of mirror that forms an image 6.2 cm behind mirror of an object placed at 26 cm in front of mirror?

Answer 1

$using \: lens \: fromula \\ \frac{1}{v} + \frac{1}{u } = \frac{1}{f} \\ \frac{1}{26} + \frac{1}{6.2} = > \: \frac{1}{26} + \frac{10}{62} = > \: \frac{31 + 130}{806} = > f = \frac{806}{161} = 5.0062$
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