Math, asked by rkvgmailcom3238, 11 months ago

Find form different solutions from the linear equation
3x+5y= 15

Answers

Answered by kpopgirl63
3

Answer:

Heya there is your answer.

Step-by-step explanation:

Let x=0 and solve for y (y-intercept)

3(0)+5y=15

0+5y=15

5y=15

5y/5=15/5

y=3

One solution is: (0,3)

:

Let y=0 and solve for x. (x intercept)

3x+5(0)=15

3x+0=15

3x=15

3x/3=15/3

x=5

Your second solution is (5,0)

:

The next two points, I'm going to pick are letting x=-10 and x=10. I know that they will work out to be whole numbers, it takes practice to find the easiest points.

Let x=-10 and solve for y.

3(-10)+5y=15

-30+5y=15

30-30+5y=15+30

5y=45

5y/5=45/5

y=9

Your third solution is: (-10,9)

:

Let x=10 and solve for y.

3(10)+5y=15

30+5y=15

-30+30+5y=-30+15

5y=-15

5y/5=-15/5

y=-3

Your fourth solution is: (10,-3)

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