Question

find four consecutive no. whose sum is 96
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Answer 1

Answer:

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Answer 2

$let \:the\:four \:consecutive \:numbers\:be\:$ $x\: ,x+1\: ,x+2,\:x+3$

x+x+1+x+2+x+3=96

4x+6=96

4x=96-6

4x=90

x=90/4

x=22.5

x=22.5

x+1=23.5

x+2=24.5

x+3=25.5

$therefore \: four \:consecutive \:numbers\:are\:$ $22.5,23.5,24.5,25.5$