Question

find four consecutive number whose sum is 74

Answer 1

1st no = x

2nd = x+1

3rd = x+2

4th = x+3

sum = 74


x+x+1+x+2+x+3 = 74

4x +6 = 74

4x = 74-6

4x = 68

x = 68/4

x = 17

 numbers  = 17,18,19,20

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-p.priyamvatha

Answer 2

Let us denote four consecutive integers as:
x, (x+1), (x+2), ( x+3)
4x + 6= 74
4x= 74- 6
4x = 68
X = 68/4
X= 17
The integers are as follows:
X = 17
X+1 = 18
X+2= 19
X+3= 20