find four consecutive numbers such that the three time find largest number added to twice the smallest number is 93 which of these are prime no.
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Step-by-step explanation:
Let 1st no be x
2nd no = x+2
3rd no = x+4
4th no = x+6
A/q
3(x+6) + 2x = 93
3x+18 +2x = 93
3x+2x = 93 -18
5x = 75
x=15
1st no = 15
2nd no = 17
3rd no = 19
4th no = 21
Among these2nd and 3rd no. are prime no.
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