Math, asked by sanjay3389, 11 months ago

find four consecutive numbers such that the three time find largest number added to twice the smallest number is 93 which of these are prime no.​

Answers

Answered by prashant42
1

Step-by-step explanation:

Let 1st no be x

2nd no = x+2

3rd no = x+4

4th no = x+6

A/q

3(x+6) + 2x = 93

3x+18 +2x = 93

3x+2x = 93 -18

5x = 75

x=15

1st no = 15

2nd no = 17

3rd no = 19

4th no = 21

Among these2nd and 3rd no. are prime no.


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Answered by Prahem54
0

this is the answer of ur questions

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