Question

find four diffrtent solution of the linear equation 2x+3y=12​

Answer 1

$<b>❤❤HEY MATE!!!!❤❤$

❤❤HERE IS YOUR ANSWER!!!❤❤

➡Four solutions of linear equation 2x+3y=12 are as given below:-

1) Let x be 0 , So ,

➡2x+3y=12

➡2(0)+3y=12

➡0+3y =12

➡y = 12/3 = 4

So , x = 0 and y = 4

2) Let x be 1 , so ,

➡2x+3y=12

➡2(1)+3y=12

➡2+3y=12

➡3y=12-2

➡3y=10

➡y =10/3

Hence, x =1 and y = 10/3

3) Let x be 2 , so ,

➡2x+3y=12

➡2(2)+3y=12

➡4+3y=12

➡3y=12-3

➡3y=9

➡y=9/3=3

Hence, x = 2 and y = 3

4) Let x be 3,so,

➡2x+3y=12

➡2(3)+3y=12

➡6+3y=12

➡3y=12-6

➡3y=6

➡y=6/3=2

Hence, x = 3 and y = 2.

✌✌HOPE IT HELPS✌✌

➡

Answer 2

I know only one answer x=4 and y=2......

I hope my answer will help yoy