Question

Find four integral solutions for the linear equation 4 − 5 − 15 = 0​

Answer 1

Step-by-step explanation:

4-5-15=0

4X-5Y=15

On putting Y=0,we get

4X-5(0)=15

4x=15

x=15/4

on putting x=0, we get

4(0)-5Y=15

0-5y=15

-5y=15

y=15/5=3

on putting x=1,we get

4(1)-5Y=15

4-5y=15

-5y=15-4

-5y=11

-y=11/5

on putting y=1,we get

4X-5(1)=15

4X-5=15

4x=15+5

4X=20

x=5

Four integer(15/4,0),(0,3),(1,11/5),(5,1)