Question

find four numbers in A.P such that the sum of 2nd and 3rd terms is 22 and the product of 1st and 4th terms is 85.

Answer 1

Answer:

17, 13, 9, 5

Step-by-step explanation:

Let the numbers be  

a-3d, a-d, a+d, a+3d

(a - d) + (a + d) = 22 \\ a = 11

(a - 3d)(a + 3d) = 85 \\  {a}^{2}  - 9 {d}^{2}  = 85 \\ 9 {d}^{2}  =  {11}^{2}  - 85 = 36 \\ d =  \sqrt{4}  = 2 \:  \: or \:  \:  - 2

So the numbers are

5, 9, 13, 17

17, 13, 9, 5

Answer 2

Answer:

This is the ans. 17,13, 9,5