find Four solutions for the given equation x+y=3
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0
Answer:
Now,
3x+y=7
forx=0
3(0)+y=7
∴y=7
fory=0
3x+0=7
3x=7
x=
3
7
forx=1,
3(1)+y=7
y=
3
7
fory=1
3x+1=7
3x=6
x=
3
6
=2
So four solutions of the given equations are;
(0,7)(
3
7
,0)(1,
3
7
)(2,1)
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