find frictional force acting on the block ?
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Answered by
1
Answer:
6N is the maximum friction it can apply, however, there is no force in the horizontal direction so the frictional force should be zero.
Explanation:
Normal force=Exerted force+mg
=10+50=60N
Frictional force=
(constant of static friction×N)=(0.1×60)
=6N
Answered by
0
Answer:
6N is the maximum friction it can apply, however, there is no force in the horizontal direction so the frictional force should be zero.
Explanation:
Normal force=Exerted force+mg
=10+50=60N
Frictional force=
(constant of static friction×N)=(0.1×60)
=6N
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