Question

Find gp for which the sum of 1st 2 terms is -4 and the fifth term is 4 tines the 3rd term

Answer 1

Answer:

Step-by-step explanation:

S2=-4

S5=4 (a3)

Solution

S2=-4

2÷2 [2a+d]=-4

2a+d=-4 -i

S5=4 (a3)

5÷2 (2a+4d)=4 (a+2d)

a=-2d

Substitute a in i

2a+d=-4

2 (-2d)+d=-4

d=4/3

Put the value of d in a

a=-2nd

a=-2 (4/3)

a=-8/3

Therefore Ap

-8/3,-4/3,0.......