Question

Find greatest no of ,4 digits divisible by 15,25,40and75

Answer 1

We have to find greatest four digit no divisible by 15, 25, 40, & 75
LCM of these no = 2*2*2*3*5*5
= 600.
Now divide greatest four digit no 600 i.e. divide 9999 by 600.
Remainder will be 399.
it means if we subtract 399 from 9999, then we will get required answer .
so, 9999-399,= 9600.

So answer is : the greatest four digit no divisible by 15,25,40 & 75 = 9600

Hope it help you !!!