Question

find greatest number that divides 43,91,183 leaving same remainder in each case

Answer 1

subtract the same number from each of these
take 3
43-3=40
91-3=88
183-3=180

find HCF of 40,88 and 180

which is 4

so the number is 4

hope helps

Answer 2

Answer:

4

Step-by-step explanation:

required number = HCF of (91-43), (183-91), (183-43)

∴ HCF of 48,92,140=

By euclid's division lemma:

92=48x1+44

48=44x1+4

44=4x11+0

for 140:

140=4x35+0

∴The required number highest number is 4.

RS Agarwal class 10→page 18→question number 23