Find H.C.F. and L.C.M. of x3-y3, x2-y2 and (x-y) ?
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write all the polynomial product of factors
1) x³-y³ = (x-y)(x²-xy+y²)
2)x²-y² =(x-y)(x+y)
3)x-y = (x-y)
hcf = (x-y)
lcm = (x-y)(x²-xy+y²)(x+y)= (x³-y³)(x+y)
1) x³-y³ = (x-y)(x²-xy+y²)
2)x²-y² =(x-y)(x+y)
3)x-y = (x-y)
hcf = (x-y)
lcm = (x-y)(x²-xy+y²)(x+y)= (x³-y³)(x+y)
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Answer:
write all the polynomial product of factors
1) x³-y³ = (x-y)(x²-xy+y²)
2)x²-y² =(x-y)(x+y)
3)x-y = (x-y)
hcf = (x-y)
lcm = (x-y)(x²-xy+y²)(x+y)= (x³-y³)(x+y)
Step-by-step explanation:
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