Find H.C.F. of 65 and 117 and express it in two different way of the form 65 m + 117 n.
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Hey user !!
Here is your answer !!
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Firstly HCF of 65 and 117
117 = 1 (65) +52
65 = 1 (52) +13
52 = 4 (13) + 0
Hence 13 is the Hcf
Now,
65m + 117 n = 13
65 (2) + 117 (-1) =13
130 - 117 = 13
So m= 2 ,n= -1
Hope it is satisfactory :-)
_________________________________________⭐
Here is your answer !!
_____________________________________________⭐
Firstly HCF of 65 and 117
117 = 1 (65) +52
65 = 1 (52) +13
52 = 4 (13) + 0
Hence 13 is the Hcf
Now,
65m + 117 n = 13
65 (2) + 117 (-1) =13
130 - 117 = 13
So m= 2 ,n= -1
Hope it is satisfactory :-)
_________________________________________⭐
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