Question

Find H.C.F OF roots of linear equations system x + 2y = 12 ; 2x -3y =3

Answer 1

Answer:

3

Step-by-step explanation:

x+2y=12

2x-3y=3

i am using the process of substitution-

x=12-2y     [from the first equation]

substitute the value of x in the 2nd equation

2(12-2y)-3y=3

24-4y-3y=3

24-7y=3

7y=21

y=3

substitute this value of y in the equation x=12-2y

x=12-2(3)=12-6

x=6

HCF of 6 and 3

6=3*2*1

3=3*1

COMMON FACTOR OR HCF =3

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