find HCF and LCM of 404 and 96 and verify that HCF and LCM product of two given numbers
Answers
Answered by
4
404=2×2×101
96=2×2×2×2×2×3
hcf {404,96}= smallest power of each common prime factor
= 2×2=4
lcm{404,96}=2×2×2×2×2×101×3=9696
hence the hcf is 4 and lcm is 9696
verification:- hcf×lcm=product of two no.
4 ×9696=404×96
38784=38784
hence verified
96=2×2×2×2×2×3
hcf {404,96}= smallest power of each common prime factor
= 2×2=4
lcm{404,96}=2×2×2×2×2×101×3=9696
hence the hcf is 4 and lcm is 9696
verification:- hcf×lcm=product of two no.
4 ×9696=404×96
38784=38784
hence verified
Answered by
1
Hi friend!!
404 can be expressed as 2×2×101
96 can be expressed as 2×2×2×2×2×3
H.C.F of the given numbers is 2×2=4
L.C.M.of the given numbers=2×2×101×8×3=9696
Product of H.C.F and L.C.M=9696×4=38784
Product of two numbers=404×96=38784
Therefore, Product of H.C.F and L.C.M=Product of two numbers
Hence proved.
I hope this will help you;)
404 can be expressed as 2×2×101
96 can be expressed as 2×2×2×2×2×3
H.C.F of the given numbers is 2×2=4
L.C.M.of the given numbers=2×2×101×8×3=9696
Product of H.C.F and L.C.M=9696×4=38784
Product of two numbers=404×96=38784
Therefore, Product of H.C.F and L.C.M=Product of two numbers
Hence proved.
I hope this will help you;)
Similar questions