find HCF of 12576 and 4052 using euclid's division algorithm
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4052..................
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Hey mate, here is your answer...
HCF of 12576 and 4052 using Euclid's Division Algorithm
12576=4052×3+420
4052=420×9+272
420=272×1+148
272=148×1+124
148=124×1+24
124=24×5+4
24=4×6+0
Hence, the HCF is 4
HOPE it helps!!!!!!
HCF of 12576 and 4052 using Euclid's Division Algorithm
12576=4052×3+420
4052=420×9+272
420=272×1+148
272=148×1+124
148=124×1+24
124=24×5+4
24=4×6+0
Hence, the HCF is 4
HOPE it helps!!!!!!
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