Math, asked by OsasJ7387, 9 months ago

Find hcf of 126,144,204 by euclid algorithm

Answers

Answered by Anonymous
3

Answer:

1st number = 2^2 x 3^3 x 5^5 x 7^0 x 11^0

2nd number = 2^3 x 3^2 x 5^2 x 7^1 x 11^0

3rd number = 2^4 x 3^4 x 5^1 x 7^2 x 11^1

Then we take the lowest exponent for all the prime factors

They are:

2^2

3^2

5^1

7^0 (note that for 7 and 11, the lowest exponent is 0 not 1)

11^0

Multiply them all for the HCF

HCF = 2^2 x 3^2 x 5^1 x 7^0 x 11^0 = 4 x 9 x 5 x 1 x 1 = 180

Step-by-step explanation:

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