Question

find hcf of 1425 and 49 by euclid division algorithm​

Answer 1

here is your answer .....

Answer 2

$hello \: mate$

➡1425=49×29+4

➡49=4×12+1

➡4=1×4+0

Since, the remainder is zero the process stops. And at this stage the divisor is 1.

Therefore, HCF(1425,49)=1