If the chords of contant of tangents from two points (x1,y1) and (x2,y2) to the ellipse
x2/a²+y2/b2=1 are at right angles then
x1x2/y1y2=
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Solution :-
equation of chord of contact (x1 , y1)
and (x2 , y2) are S1=0 and S2= 0 .
=> x x1/a² + yy1/b² = 1 and
xx2/a² + yy2/b² = 1
the product of slope is -1 .
We get , x1x2/y1y2 = -a²/b⁴
Therefore , correct answer is -a²/b⁴.
_______________________________
Solution :-
equation of chord of contact (x1 , y1)
and (x2 , y2) are S1=0 and S2= 0 .
=> x x1/a² + yy1/b² = 1 and
xx2/a² + yy2/b² = 1
the product of slope is -1 .
We get , x1x2/y1y2 = -a²/b⁴
Therefore , correct answer is -a²/b⁴.
_______________________________
Answered by
0
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