Question

Find HCF OF 1702 and 1998 by prime factorisation?

Answer 1

HCF (A,B)
a=bq+r
1998=1702×1+296
1702=296×5+222
296=222×1+74
222=74×3+0
HCF (1702,1998)=74.

Answer 2

Answer:

firstly,hcf of 1702 is

2/1702

851/851 (851 is a prime number it is not divided with any number exept 851)

1/1

secoundly,hcf of 1998

2/1998

3/999

3/333

3/111

3/37

37/1 (37 is a prime number)